
Anthony T. answered 01/13/21
Patient Science Tutor
a. More than 2 m. First calculate the total distance from the point of the jump-off to the water. This is given by S = 1/2 g t2. As the time required to reach the water is given as 1.6 s, the distance to the water is 12.54 m. The time for her to fall 2 m at which time you jump is t = √2m x 2/ 9.8 ms-2 = 0.639 s. The friend will travel an additional (1.6 - 0.639) 0.961s before hitting the water during which time you will have fallen S = 1./2 g t2 = 1/2 x9.8 x 0.9612 = 4.53 m. As the height of the drop was 12.54 m and at the time your friend hit the water, you had fallen 4.53 m, the separation between you would be about 8 m.