
Patrick B. answered 01/13/21
Math and computer tutor/teacher
6 | 1 -9 14 36 -72
6 -18 -24 72
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1 -3 -4 12 0
x^3-3x^2 - 4x + 12 = 0
x^2(x-3)-4(x-3) = 0
(x^2-4)(x-3) = 0
(x+2)(x-2)(x-3)=0
the solution set is x={2, -2, 3, 6}