A 70 kg woman is jogging, and she has 725 J of energy. How fast is she jogging?

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Answer 1

If you are jogging, you could say that your "energy" is associated with your velocity and is kinetic energy.

Kinetic energy (E_K) equals 1/2 times your mass times your velocity squared. (E_K = 1/2mv²)

E_K = 1/2mv²

v² = 2E_K/m

v = √(2E_K/m)

v = √(2(725)/70)

v = √20.714

v = 4.55 m/s

Since the "givens" have only 1 sig fig (70 kg), I would round the answer to 1 sig fig and say v = 5 m/s