Raymond B. answered 10/06/23
Tutor
5
(2)
Math, microeconomics or criminal justice
y=a(x-1)^2+3
-3=a+3
y=-6(x-1)^2+3
or
x=a(y-3)^2+1
2= 36a+1
a=1/36
x=(1/36)(y-3)^2+1
Toynua N.
asked 01/08/21Need equation for parabola in vertex form
Vertex (1 3 ) point (2 -3)
Raymond B. answered 10/06/23
Math, microeconomics or criminal justice
y=a(x-1)^2+3
-3=a+3
y=-6(x-1)^2+3
or
x=a(y-3)^2+1
2= 36a+1
a=1/36
x=(1/36)(y-3)^2+1
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