Write a polynomial function f (x) in expanded form where the only zeros are −1 , 4 , and 7 .

Answer 1

In factored form we have f(x)= a(x + 1)(x - 4)(x - 7) where a ≠ 0 any real number.

So in standard form f(x) = a(x + 1)(x² - 11x + 28) = a(x³ - 10x² + 17x +28)

Answer 2

f(x) = (x+1)(x-4)(x-7) = (x+1)(x²-11x + 28) = x³-11x²+28x+x²-11x+28

=x³-10x²+28x+28