Hasan T.

asked • 01/05/21

Question of Physics

A half uniform annulus of inner and outer radii R1 and R2 has a nonuniform surface mass density given by σ = σ0 r where σ0 is a positive constant and r is the radial distance from the origin (radial coordinate in the cylindrical coordinates). Find

i) the mass of the half annulus, and

ii) the position of the center of mass, i.e., (xcm, ycm) the center of mass in terms of R1 and R2.

1 Expert Answer

By:

Hasan T.

I understand that Dr Gulshan. I am waiting second part. Thanks for helping :)
Report

01/08/21

Dr Gulshan S.

tutor
Best, Dr Gulshan S
Report

01/08/21

Dr Gulshan S.

tutor
Ok I will send you shortly
Report

01/08/21

Dr Gulshan S.

tutor
For this we need to know center of mass of a ring (Xcm, Ycm ) ring = (0, 2r/pi) Ycm of Half disc = ∫ dm/ Mass of Complete Disc *( y ring) where dm = mass of ring Mass of Complete disc = 2 ( (σ0 pi) (R2 3 - R1 3 )/3) Plug in dm == σ0 pi r^2 dr Integrate now from R1 to R2 and find Y cm Xcm will be zero due to symmetry ONLY THING to KNOW is CM of Ring ( 0, 2r/pi) for starting point Ans ( 0, Ycm half disc)
Report

01/08/21

Dr Gulshan S.

tutor
Tell me if you still need help
Report

01/08/21

Clara R.

I didn't understand the steps of second part could you please write them in order
Report

01/14/21

Dr Gulshan S.

tutor
You start with center if mass of ring as (Xcm , Ycm) as ( 0, 2r/pi) So for whole disc integrate with limits R1 to R2 Using same method as in part 1
Report

01/15/21

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.