
Patrick B. answered 01/04/21
Math and computer tutor/teacher
2| 43x - 5 | <= 5
| 43x - 5 | < = 5/2
43x - 5 <= 5/2 or 43x - 5 >= -5/2
43x <= 5/2 + 5 43x > = -5/2 + 5
43x <= 5/2 + 10/2 43x >= -5/2 + 10/2
43x <= 15/2 43x >= 5/2
x <= 15/86 x>=5/86, which is
the same as 5/86 <=x
putting them together:
5/86 <= x <= 15/86
check:
low endpoint
x=5/86 --> 2 | 43 * 5/86 - 5 |
= 2 | 5/2 - 5 |
= 2 | 5/2 - 10/2 |
= 2 | -5/2 |
= 2 (5/2) = 5, so yes it checks
upper endpoint
x = 15/86
2 | 43(5/86) - 5 |
2 | (5/2) - 5 |
2 | 5/2 - 10/2 |
2 | -5/2 |
2 (5/2) = 5, so yes it checks
in between:
x = 10/86
2| 43(10/86) - 5 |=
2 | 10/2 - 5 | =
2| 5 -5 | =0 <=5, so yes it checks
too small:
x=0
2 | 0 - 5| = 2(5) = 10 <=5
Fails as expected
too big:
x=1
2|43-5| = 76 <= 5
Fails as expected
PROVEN answer:
5/86 <= x <= 15/86