
Michael M. answered 12/28/20
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
The question is asking you to find the derivative of f(x), f '(x)
First, calculate f(x+h)
f(x+h) = 2(x+h)2 = 2(x2 + 2xh + h2) = 2x2 + 4xh + 2h2
Thus, lim (h→0) ( f(x+h) - f(x) )/h
= lim (h→0) ( (2x2 + 4xh + 2h2) - (2x2) )/h
= lim (h→0) (4xh + 2h2) /h
= lim (h→0) (4x + 2h) = 4x
Part b is the same as part a except x has been replaced with -1, so the question is asking you to find f '(-1)
Plug in -1 for x in f '(x)