S =77 +45.50 Cos ( pit/6)
at t=0
S = 77+ 45.50 = 122.50
So graph c is correct
For Max or Min dS/dt = 0
dS/dt = - 45.50 (pi/6) Sin pit/6 ) =0
So for max t = 0, 12, 24 ,... years
For Min t = 6, 18,......... years
Aerin H.
asked 12/19/20S = 77.00 + 45.50 cos (πt /6)
where S is the sales in thousands of units and t is the time in months, with t = 1 corresponding to January.
(a) Use a graphing utility to graph the sales function over the one-year period.
![]() |
![]() |
![]() |
![]() |
left graph = a
right graph = b
below to the left = c
below to the right = d
(b) Use the graph in part (a) to determine the months of maximum and minimum sales
minimum:
maximum:
S =77 +45.50 Cos ( pit/6)
at t=0
S = 77+ 45.50 = 122.50
So graph c is correct
For Max or Min dS/dt = 0
dS/dt = - 45.50 (pi/6) Sin pit/6 ) =0
So for max t = 0, 12, 24 ,... years
For Min t = 6, 18,......... years
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.