Shane P. answered 12/18/20
I love math, math games, puzzles, applications, and puns
We have 2 equations
Area A=L*W
Perimeter P=2L+2W 200=2L+2W Solve this for L L=100-W
This means area can be written as a function of the Width
A=(100-W)*W
Sophie G.
asked 12/18/20john henry will build a rectangular corral using 200 meters of barbed wire. describe the area of the corral are a function of one of its sides.
Shane P. answered 12/18/20
I love math, math games, puzzles, applications, and puns
We have 2 equations
Area A=L*W
Perimeter P=2L+2W 200=2L+2W Solve this for L L=100-W
This means area can be written as a function of the Width
A=(100-W)*W
Raymond J. answered 12/18/20
Patient with Ability to Explain in Many Ways
Area of a rectangle = Width • Length ⇒ A = W•L
Since there are 200' of wire to form the rectangle, the perimeter = 200.
Perimeter = sum of all sides = Length + Length + Width + Width ⇒ 2•Length + 2•Width = 2L+2W = 200.
2L = 200 - 2W ⇒ L = 100 - W
substituting above we get A = W•(100 - W)
Perimeter = 200 = 2(L+W) = 2L+2W
2L = 200-2W
L = 100-W
Area = LW = (100-W)W = 100W-W^2
A = 100W-W^2
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