Brett P. answered 12/19/20
This probability example is easier to solve if you calculate the chance of not winning and take the opposite. The wording is a confusing, but this is what I mean:
If you have 1 ticket: The chance you don't win on the first draw is 99/100. The chance you don't win on the second draw is 98/99, third 97/98,... The chance you don't win at all is these 5 scenarios multiplied by each other, which will equal .95. The chance you win with that one ticket would be (1 - .95) or .05.
The same applies if you have 10 tickets: The chance you don't win on the first draw is 90/100. The chance you don't win on the second draw is 89/99, third 88/98,...The chance you don't win at all is these 5 scenarios multiplied by each other, which will equal approximately .584. The chance you win atleast once, would be approximately (1 - .584) or .416.