Tom K. answered 12/14/20
Knowledgeable and Friendly Math and Statistics Tutor
This will be approximated by the eigenvector for the eigenvalue with eigenvector = 1
Let z = 1
From the second column, 1/2x + 7/10y = y
From the third column, 1/2x + 1/2 = 1
Rewriting,
1/2x - 3/10y = 0
1/2x = 1/2
x = 1
(1/2)(1) - 3/10y = 0
1/2 = 3/10y
y = 5/3
(1, 5/3, 1) normalizes to
(3/11,5/11,3/11)
With the initial probability vector equal to the eigenvector, there will be the same values at every iteration.