Michael J. answered 02/23/15
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Effective High School STEM Tutor & CUNY Math Peer Leader
p(x) = x3(x+1)2
p(x) = x3(x+1)(x+1)
To find the x-intercepts, we set p(x) equal to zero.
p(x) = 0
x3(x+1)(x+1)=0
x3 = 0 or x = 0
x+1=0 or x = -1
The x-intercepts are (0,0) and (-1,0).
To find the y-intercepts, we evaluate p(x) when x=0.
p(0) = 03(0+1)2
p(0) = 0
The y-intercept is (0,0).