A 2 kg ball on a string is rotated about a circle of radius 10 m. The maximum tension allowed in the string is 50 N. What is the maximum speed of the ball?

Answer 1

The tension in the string is the magnitude of a " center seeking " force called the centripetal force ( Fc ). Fc = ( mv^2 ) / r ). So, if 50N of force keeps the ball in orbit, the 50N = ( mv^2 / r ). Therefore, the square root ( sqrt ( 50N*r / m ) = v. The sqrt ( 50*10m / 2kg ) = v.

v = 15.8 m/s.