mathematical pendulum

Question

Let the oscillation time of a mathematical pendulum be 5 seconds. How does this change when we take it to the moon?

Answer 1

Time period of a pendulum is given as T = 2pi (L/g) ^1/2

Value of g a t moon is 1/6th of the value at earth

Value of T at moon will be

T' = T √6

So if pendulum has time period on earth as 5 sec , it will be 5 √ 6 = 5*2.449= 12.25 Sec