
Sydney D. answered 12/11/20
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Let n represent 1,2,3,4,..., infinity
If we substitute our n-values into the equation 2 * 3n-1 it would look like this:
n = 1 --> 2*31-1 = 2*30 = 2*1 = 2
n = 2 --> 2*32-1 = 2*31 = 2*3 = 6
n = 3 --> 2*33-1 = 2*32 = 2*9 = 18
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and so on and so forth.
Therefore the correct answer is option c.