What average force is required to stop a 950-kg car in 9.2 s if the car is traveling at 95 km/h (**Needs to be in m/s)

Answer 1

Use F = ma (newton's II law)

a = (v2-v1)/t

F = m(v2 - v1) /t

F = - m v1 / t = () N

[v2=0] - ve sign telling about the direction of force.

v2 = 95 km/h = 95 * 1000m/(60*60 s)