If e2y-e(y^2-y)=x4-x,2 then the value of dy/dx at the point (1,0) is

Question

If e^2y-e^{(y^2-y)}=x⁴-x,² then the value of dy/dx at the point (1,0) is

A) 0

B) 1/2

C) 2/3

D) 2

Answer 1

I agree with Stanton D.

Maybe I can give you a start.

For implicit differentiation you need to use the chain rule, as follows

2e^2y(dy/dx) - e^{(y^2-y)}(2y-1)(dy/dx) = 4x³ - 2x

Now collect terms and proceed as Stanton D. has suggested.