A 792 kg rollercoaster car is on the Inside of a loop of radius 18.7 m. At the top of the loop, the car moves at 17.3 m/s. What is the normal force on the car at that point?

Answer 1

The normal force + weight of the car is equal to the net force which is the centripetal force.

Solve for normal force and substitute mg for weight and mv²/r for centripetal force.