Find the lengths of the sides of the triangle.

Question

Side a is "x"

Side b is "x+6"

Side c is "x+7"

Answer 1

well IF it's a right traingle, pythagorus says:

x^2 + x^2+12x+36 = x^2+14x+49

2x^2 + 12x+36 = x^2 + 14x+49

x^2 - 2x - 13 = 0

quadratic formula says:

[2 + sqrt(56)] / 2 = [2 + 2*sqrt(14)]/2 = 1+sqrt(14)

x=4.74166.. is the approximation per quadratic formula...

a=1+sqrt(14), b=7+sqrt(14), c=8+sqrt(14)

pythagorean check....

a^2 + b^2

1+2*sqrt(14)+14 + 49+14*sqrt(14)+14 =

78 + 16*sqrt(14) + 14

while

c^2 = 64 + 16*sqrt(14) + 14 = 78+16*sqrt(14)

there is our bonifide attempt, pending student REPOST with more necessary information..

this problem is CLOSED and I took one for the team..