Patrick B. answered 12/05/20
Tutor
4.7
(31)
Math and computer tutor/teacher
The statement is false....
a=2 > 1=b for a=2 and b=1 both positive integers...
b^a = 1^2 =1 while a^b = 2^1 = 2
in fact for b=1 and any positive integer a>1=b,
b^a = 1^a = 1 while a^b = a^1 = a > 1 = b^a