Nikki C. answered 04/11/25
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To find a polynomial with integer coefficients, a leading coefficient of 1, and the least degree for the zeros −1−1, 22, and −i−i, we also need to include the conjugate ii.
The zeros are:
- −1−1
- 22
- −i−i
- ii
The polynomial is formed by multiplying the factors corresponding to these zeros:
f(x)=(x+1)(x−2)(x+i)(x−i)f(x)=(x+1)(x−2)(x+i)(x−i)
Simplify the complex conjugate pairs:
(x+i)(x−i)=x2+1(x+i)(x−i)=x2+1
Now, the polynomial is:
f(x)=(x+1)(x−2)(x2+1)f(x)=(x+1)(x−2)(x2+1)
Expand and combine like terms:
f(x)=(x2−x−2)(x2+1)=x4−x3−x2−x−2f(x)=(x2−x−2)(x2+1)=x4−x3−x2−x−2
So, the polynomial function is:
f(x)=x4−x3−x2−x−2f(x)=x4−x3−x2−x−2
This is the polynomial with integer coefficients, a leading coefficient of 1, and the least degree for the given zeros.