In ΔUVW, v = 530 cm, ∠V=129° and ∠W=43°. Find the area of ΔUVW, to the nearest square centimeter.

Answer 1

A = (a)(b) sin C / 2

Use Law of Sines to determine VW.

Then

A = (530)(VW) sin 8° / 2

Answer 2

law of sines:

sin 129/530 = sin 43/w

cross multiplies:

sin 129 * w = 530 * sin 43

solves for w:

w = 530 * sin 43 / sin 129

= 465.11099427895247710150933017028

-------------------------------------

sin 129/530 = sin 8/u

cross multiplies:

sin 128 * u = sin 8 * 530

u = sin 8*530/sin 128

= 93.604996088222769463457532515792

Heron's formula gives the area:

16,708.727461714