Johnny T. answered 12/03/20
Experience C/C++ and Objective-C Software Engineer
Forces are vectors. When calculating torques for forces, only the perpendicular component of the force to the line of action accounts for the resulting torque; therefore, starting with F1:
- T1 = - ( 3m ) F1 = - (3m) (3N) = - 9 Nm
- T2 = + ( 2m ) F2 · cos ( 300 ) = + (2m) (2N) cos(300) = 3.464 Nm
- T3 = 0; this contributes nothing because it passes through the axis itself
- T4 = - ( 2m ) F4 = - (2m) (1.8N) cos(200) = - 3.383
The total torque is found by adding each of these torques:
- T = T1 + T2 + T3 + T4
- T = ( - 9 N·m ) + ( 3.464 N·m ) + 0 - ( 3.383 N·m)
- T = - 8.92 N·m
Because the result is negative, the torque is into the paper.
Ina S.
Thank you so much! This helped me a lot :)12/03/20