Emmi G. answered 11/29/20
Experienced math and science tutor
Hello!
So here we have a triangle with sides a, b, c and angles A,B,C
Something to note: Sine rule: a/sinA=b/sinB=c/sinC
Find B:
a/sinA=b/sinB.
sinB=bsinA/a (solve for angle B)
sinB=(9.2)sin(76.2)/(12.4)
B= 46.1°
Find C:
Triangle is 180°
A+B+C=180°
180°-A-B=C
180°-76.2°-46.1°=57.7°
C=57.7°
Find c:
using ratio of side to sine angle:
a/sinA=c/sinC
c=sinCa/sinA (algebra)
c=sin(57.7)(12.4)/sin(76.2)
c=10.8
Hope this helps!