equation of ellipse is x^2/b^2 + y^2/a^2 = 1
vertices are (0,+/-a), so if vertex is (0,6), then a is 6 and a^2 is 36.
foci are (0, +/- c), so if focus is (0,3), then c is 3
c^2 = a^2 - b^2
9 = 36 - b^2
b^2 = 27
so equation is x^2/27 + y^/36 = 1
Gaukhar M.
asked 11/25/20Give the equation in standard form of the ellipse centered at the origin with a focus at (0,3), and a vertex at (0,6).
equation of ellipse is x^2/b^2 + y^2/a^2 = 1
vertices are (0,+/-a), so if vertex is (0,6), then a is 6 and a^2 is 36.
foci are (0, +/- c), so if focus is (0,3), then c is 3
c^2 = a^2 - b^2
9 = 36 - b^2
b^2 = 27
so equation is x^2/27 + y^/36 = 1
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