How would I solve this? I have been stuck on this homework question for a bit.

Question

The most dreaded time of year is approaching and Tommy Turkey is plotting his escape from the farm. At 18.1 kg, he is too fat to fly away, but he can flutter his wings well enough to hop over the 8.69 m fence.

If Tommy managed to get a horizontal velocity of 1.886 m/s when he barely clears the top of the fence. How far outside the pen does he land?

Answer 1

Step 1: Find the time it takes for the turkey to go from the top of the fence to the ground.

y_f = y₀ + v_0,yt + 0.5a_yt²

y_f = final position = 0 m

y₀ = initial position = 8.69 m

v_0,y = initial velocity in y-direction = 0 m/s

a_y = acceleration in y-direction = -9.8 m/s²

8.69 = 4.9t²

t = 1.33 sec

Step 2: Use this time to find the horizontal distance away from the pen the turkey landed.

x_f = x₀ + v_0,xt + 0.5a_xt²

x₀ = initial position = 0 m

v_0,x = initial velocity in x-direction = 1.886 m/s

t = time = 1.33 s

a_x = acceleration in the x-direction = 0 m/s²

x_f = (1.886)(1.33)

x_f = 2.51 m