Tom K. answered 11/23/20
Knowledgeable and Friendly Math and Statistics Tutor
a shortcut: the semicircles make a hemisphere, so the volume is 2/3πr3 = 2/3π23 = 16/3 π
Since the isosceles triangles would each have, where half the cross-section has length c, area c2 because the hypotenuse is 2c, so legs are each √2 c, and A = 1/2(√2 c)2 = c2, while the semicircles have cross-section π/2 c2, 2/π (16/3 π) = 32/3
The long way: each semicircle at x will have radius ⋅√(4-x2),so ∫22 π/2 (4 - x2) dx =
π/2 (4x - x3/3)|-22 =
π/2((4*2-23/3)-(4*-2 - (-2)3/3)) =
π/2(16 - 16/3) =
16/3π
each triangle will have area ⋅4-x2,so ∫22 (4 - x2) dx =
(4x - x3/3)|-22 =
((4*2-23/3)-(4*-2 - (-2)3/3)) =
(16 - 16/3) =
32/3
Shannen M.
Hello, thank you so much for your help, it makes a lot more sense now! Just for part (a) I think the answer should be 16π/3.11/23/20