
Mark M. answered 11/23/20
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
To be undefined
x - 5 = 0
x = 5
(x + 2)(x + 5) = x2 + kx + p
x2 + 7x + 10 = x2 + kx + p
k = 7, p = 10
Anna M.
asked 11/22/20Let f(x)= x^2+kx+p/x-m have zeros for x at -2 and -5 and be undefined when x=3. Find (2k+3p+4m)
Mark M. answered 11/23/20
Mathematics Teacher - NCLB Highly Qualified
To be undefined
x - 5 = 0
x = 5
(x + 2)(x + 5) = x2 + kx + p
x2 + 7x + 10 = x2 + kx + p
k = 7, p = 10
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