What will be the acceleration down the ramp?

Question

A 15 kg box is sitting at the top of a 10 meter ramp angled at 28 degrees. Assuming there is no friction, draw a force diagram for the box. What will be the acceleration down the ramp?

Answer 1

When you apply newton's second law down the ramp, F_x = ma_x

Only force you will have is the x component of the mg, since there is no friction.

Therefore mass will cancel off and you will get below:

mgsin(theta) = ma_x

a_x=gsin(28) = 9.81xsin(28)

= 4.6 m/s²