the sum of four consecutive even integers is −28

Answer 1

You can solve any consecutive integer problem using Algebra. First, think about what the problem is asking. They want 4 consecutive integers (numbers that come after one another. e.g., 1,2,3 or, 12,13,14), but they have to be even.

You have to create an algebraic equation that asks for four consecutive and even numbers and that equals -28. That equation looks like this:

2X + (2X+2) + (2X+4) + (2X+6) = -28

X is multiplied by two to ensure that the first of the consecutive integers will be even (any number multiplied by 2 is even). Then it is added to an amount equal to itself + 2. This ensures that the next number will be the next even number.

This equation can be simplified to 8X + 12 = -28

8X + 12 = -28

8X = -40

X=-5

Plug X back into your equation:

2X + (2X+2) + (2X+4) + (2X+6) = -28

2(-5) + (2(-5)+2) + (2(-5)+4) + (2(-5)+6) = -28

-10 + -8 + -6 + -4 = -28

Answer 2

The answer is: -4, -6, -8, -10

-4-6-8-10 = -28