Tom K. answered 11/20/20
Knowledgeable and Friendly Math and Statistics Tutor
z=1/xy or
xyz = 1
xydz+ xzdy + yzdx =0
(x, y) =(1,2), so z = 1/xy = 1/(1*2) =1/2
1*2dz + 1*1/2dy + 2*1/2dx =0
2dz + 1/2dy + 1dx =0
2z +1/2y + x = C
2z +1/2y + x = 2(1/2)+1/2(2) + 1(1)= 3
2z +1/2y + x = 3,or
4z + y + 2x = 6