S P.

asked • 11/18/20

What is the value of C so that the following function is a probability density function? f(x)=Cx^9.5 --> see description

f(x)=Cx9.5 if 0≤x≤2, 0 otherwise

2 Answers By Expert Tutors

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Marc L. answered • 11/18/20

Tutor
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Marc L.

You did your integration incorrectly, add 1 to the exponent then divide by that newly increased exponent, also you can check your work by plugging that C into the equation and seeing if you get 1, yours gets about .009
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11/18/20

Mike D.

tutor
Thank you, must have been half asleep.
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11/18/20

Mike D.

tutor
The integration should have been C (x^10.5/10.5) so C (2^10.5/10.5)=1 giving C = (10.5 / 2^10.5) = 0.00725
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11/18/20

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