Hank G.
asked 11/16/20sin[Arccos(-sqrt3/2)]
Use Principal Values to evaluate. Show all work.
How do I make the graph that goes along with this?
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1 Expert Answer
Yefim S. answered 11/16/20
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5
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Math Tutor with Experience
cos{Arccos(-√3/2)] = - √3/2; sin{Arccos(-√3/2)] = √1-(-√3/2)2 = 1/2
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Hank G.
Answers in fraction form would be great, thank you!11/16/20