cos[Arcsin(-1)]

Question

Use Principal Values to evaluate. Show all work.

How do I make the graph that goes along with this?

Answer 1

the angle whose sine = -1 is 270 degrees or 3pi/2

cosine of 270 degrees or of 3pi/2 = 0

cos[Arcsin(-1)] = 0

Just draw a unit circle with two lines, the x axis and the y axis but only in the divide between quadrant III and IV. Those two lines show you the angle of 270 or 3pi/2