Problem Solving with All Three Kinematics Equations

Question

A car which is traveling at a velocity of 9.6 m/s undergoes an acceleration of 4.2 m/s2

over a distance of 450 m. How fast is it going after that acceleration?

Answer 1

This problem is readily solved by use of the equation

V_f² = V_o² + 2aS where V_f is the final velocity, V_o is the initial velocity, a is the acceleration, and S is the distance travelled during the acceleration.

Plugging in the given information, V_f² = 9.6² m^2//s²+ 2 x 4.2 m/s² x 450 m. The final result is 62 m/s.

Note: The equation given is derivable from more basic equations.