Problem Solving with All Three Kinematics Equations

Question

A car which is traveling at a velocity of 1.6 m/s undergoes an acceleration of 9.2 m/s2 over a

distance of 540 m. How fast is it going after that acceleration?

Answer 1

v² = v₀² + 2aΔx

v² = (1.6)² + 2(9.2)(540)

v² = 2.56 + 9936

v² = 9938.56

v = 99.69 m/s