Jake pulls a couch of mass 38 kg across his apartment. He pulls on the couch at an angle of 25 degrees. with a force of 300 N.

Question

Jake pulls a couch of mass 38 kg across his apartment. He pulls on the couch at an angle of 25 degrees. with a force of 300 N. The free-body diagram is shown below. What is the x-component of his applied force? What is the y-component of his applied force? Assuming the couch does not leave the ground, what is the normal force acting on the couch?

Answer 1

Mass = 38kg

Force = 300 N

Angle = 25 degree

X component = F Cos theta = 300 .Cos 25 (N) = 271.9 N

Y component = F Sin theta = 300 .Sin 25 ( N ) = 126.8 N

Wt acting downwards = mg = 38. 9.8 ( N) = 372.4 N

F.sin theta + Normal reaction = mg = 372.4 N

So Normal Reaction = 372.4 - 126.8 = 245.6 N