Michelle T. answered 11/15/20
Caltech/UCSD Engineer turned Educator (University and High School)
For this problem, you can use the fact that the area under the graph tells you the change in position.
For part a, calculate the are under the graph from t = 0 to t = 5. Over the first 3 seconds, the area under the graph (3 x 2) indicates the object moves 6 cm to the right. Over the time from t = 3 to t = 5, the area under the graph (3 x (-2)) indicates the move 6 cm to the left. So, the object goes back to its initial position.
For part b, the area under the graph is 4, so the object moves 4 cm to the right from the initial position.
For part c, it sounds like maybe they are asking for distance instead of displacement (part a asked for displacement), so that would be 6 cm + 6 cm = 12 cm.