Raymond B. answered • 5d
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L =/> 4 +5w
P> 44 = 2L +2w
2(4+5w) +2w = 44 or is greater than 44
w = width =/> 36/12 = 3
L=/> 19
Kk K.
asked • 11/08/20A rectangle has a length at least four more than five times the width. If the perimeter is at least 44 units, find the possible width.
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