
Mark M. answered 11/07/20
Mathematics Teacher - NCLB Highly Qualified
10.875 = 384 e90k
0.02832 ≈ e90k
ln 0.02832 ≈ 90k
-3.5648 ≈ 90k
-0.0396 ≈ k
0.5 ≈ e-0.096t
ln 0.5 ≈ -0.096t
-0.6931 = -0.0396t
17.5 ≈ t
Sara S.
asked 11/07/20At the beginning of an experiment, a scientist has 348 grams of radioactive goo. After 90 minutes, her sample has decayed to 10.875 grams.
A) What is the half-life of the goo in minutes?
B)Find a formula for G(t), the amount of goo remaining at time t. G(t)=
C)How many grams of goo will remain after 65 minutes?
Mark M. answered 11/07/20
Mathematics Teacher - NCLB Highly Qualified
10.875 = 384 e90k
0.02832 ≈ e90k
ln 0.02832 ≈ 90k
-3.5648 ≈ 90k
-0.0396 ≈ k
0.5 ≈ e-0.096t
ln 0.5 ≈ -0.096t
-0.6931 = -0.0396t
17.5 ≈ t
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