A 2.75 kg box is pushed with a 10.5 N force across ground where lk = 0.327. What is the acceleration of the box?

Answer 1

Given

M = 2.75 kg

F = 10.5 N

uk = 0.327

Find

a

Solution

N = mg = 2.75*9.81 = 26.977 N

fk = uk * N = 0.327 * 26.977 = 8.82 N

Sum Force X = ma

F - fk = ma

a = (F-fk)/m = (10.5 - 8.82)/2.75 = 0.610 m/s^2