Raymond B. answered 11/03/20
Math, microeconomics or criminal justice
x/(1+x) = (u-1)/u where u=1+x
then the integral of x/(1+x) = integral of (u-1)/u
(u-1)/u = u/u - 1/u = 1 - 1/u
integral of 1du = u
integral of (1/u)du = lnu
Joy C.
asked 11/03/20Find the area between the graph of and the x-axis for the interval (0, ∞). Your work must include the proper notation and show the antiderivative. If the integral diverges, show why.
Raymond B. answered 11/03/20
Math, microeconomics or criminal justice
x/(1+x) = (u-1)/u where u=1+x
then the integral of x/(1+x) = integral of (u-1)/u
(u-1)/u = u/u - 1/u = 1 - 1/u
integral of 1du = u
integral of (1/u)du = lnu
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.