Find the time required when the ball reaches the 30.9m distance.
X = Vox * t
Vox = 20.6 cos 53 = 12.4 m/s
t = X/Vox = 30.9/ ( 20.6 cos 53) = 2.49 seconds
Now, see how high the ball will be at this time
Let A be initial point, B be final point
Yb = (1/2) *a*t^2 + Voy*t+Ya
Ya = 0
Yb = -(1/2)*9.81*2.49^2 + 20.6sin53*2.49 + 0
Yb = 10.55
Ball is higher then the cross bar...
It clears it by 10.55 - 3.05 = 7.5 m
Sara H.
that was wrong, thank you tho11/02/20