Find the normal force on the ground to the object
Sum Force Y = 0
-2kg * 9.81 + Fn = 0
Fn = 2*9.81 = 19.62 N
Kinetic Friction Force = Fk = µk * Fn = µk(19.62)
µk = 0.3 (Wooden Floor)
Fk = µk * Fn = 0.3*(19.62) = 5.886 N

Belisario G.
11/02/20
Www S.
asked 11/02/20An 2 kg wooden block slides across a horizontal wooden floor at constant velocity.What is the magnitude of the force of kinetic friction between the block and the floor?
Find the normal force on the ground to the object
Sum Force Y = 0
-2kg * 9.81 + Fn = 0
Fn = 2*9.81 = 19.62 N
Kinetic Friction Force = Fk = µk * Fn = µk(19.62)
µk = 0.3 (Wooden Floor)
Fk = µk * Fn = 0.3*(19.62) = 5.886 N
Belisario G.
11/02/20
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Www S.
and what does that mean11/02/20