n=0 ---> A0 = 1/1! = 1

n=1 ---> A1 = -1/(2!) = -1/2

n=2 ---> A2 = 1/(3!) = 1/6

n=3 ---> A3 = -1/(4!) = -1/24

n=4 ---> A4 = 1/(5!) = 1/120

n=5 --> A5 = -1/720

n=6 ---> A6 = 1/5040

Clarissa M.

asked • 11/01/20What are the first four terms of this sequence, beginning with n = 0

A_{n = (-1)}^{n}

^{ (n+1)!}

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n=0 ---> A0 = 1/1! = 1

n=1 ---> A1 = -1/(2!) = -1/2

n=2 ---> A2 = 1/(3!) = 1/6

n=3 ---> A3 = -1/(4!) = -1/24

n=4 ---> A4 = 1/(5!) = 1/120

n=5 --> A5 = -1/720

n=6 ---> A6 = 1/5040

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