8sinxcosx=2cosx
8sinxcosx -2cosx =0
4cosx(4sinx-1)=0
4cosx=0 this occurs at 90 and 270 degrees
and
4sinx=1.
sinx=.25. take inverse sin
x=14.47 and (180-14.47) degrees
Gaukhar M.
asked • 11/01/20please help with this one. Thank you!
Solve for t, 0≤t<2π
8sin(t)cos(t)=2cos(t)
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