A 0.190 kg baseball is pitched to a batter with an initial speed of 15.8 m/s, if the bat delivers a force of 2.04E3 N for a time of 0.00320 s.

Question

What speed does the baseball have as it is hit back towards the pitcher?

Answer 1

Initial momentum of ball = mV1 =0.190*15.8 = 3.002 kgm/s ( -ve X direction )

Change in Momentum = Force *time = 2.04*10³ *0.00320= 6.528 kgm/s ( +ve X direction )

Total final Momentum = 3.002 + 6.528 = 9.53 kgm/s

= mv2

v2 = Final velocity =9.53/m=9.53/0.190 = 50.157 m/s , which is of ball speed towards the pitcher