Kinematics Equation2

Question

An object is moving with an initial velocity of 30 m/s. It is then subject to a constant acceleration of 4.5 m/s^2 for 9 s. How far will it have traveled during the time of its acceleration?

Answer 1

We apply the constant acceleration equations...

Given:

Vo = 30 m/s

a = 4.5 m/s^2 

t = 9 seconds

Find:

X=?

Solution:

X = (1/2) * a * t ^2 + Vot +Xo

X = (1/2) * 4.5 * 9^2 + 30*9

X = 2.25 * 81 + 270

X = 452.25 m