cos u = -12/13 (because you are dealing with a 5, 12, 13 right triangle.
cos 2u = cos2u - sin2u
cos (u/2) = sqrt[(1+cos u )/2]
Jordan Z.
asked 10/29/20cos u = -12/13 (because you are dealing with a 5, 12, 13 right triangle.
cos 2u = cos2u - sin2u
cos (u/2) = sqrt[(1+cos u )/2]
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